Question

Using Kohlrausch law write an expression for the limiting molar conductivity of acetic

acid.​

Answer 1

To do:

Using Kohlrausch law write an expression for the limiting molar conductivity of acetic acid.

Solution:

In Kohlrausch's Law, we shall express the limiting molar conductivity of acetic acid in terms of molar conductivity of other strong electrolytes.

So, we can add the limiting molar conductivity of Sodium-Acetate and Hydrochloric acid, and then subtract the limiting molar conductivity of Sodium Chloride.

$\rm \land_{m(CH_{3}COOH)}^{ \circ} = \land_{m(CH_{3}COO^{-}Na^{+})}^{ \circ} + \land_{m(HCl)}^{ \circ} - \land_{m(NaCl)}^{ \circ}$

So, final answer is:

$\boxed{ \bf{\land_{m(CH_{3}COOH)}^{ \circ} = \land_{m(CH_{3}COO^{-}Na^{+})}^{ \circ} + \land_{m(HCl)}^{ \circ} - \land_{m(NaCl)}^{ \circ}}}$

• The usefulness of this equation is in the fact that the molar conductivity at infinite dilution of weak electrolytes can be expressed with the help of known values obtained from strong electrolytes.

$\star$ Hope It Helps.

Answer 2

To do:

Using Kohlrausch law write an expression for the limiting molar conductivity of acetic acid.

Solution:

In Kohlrausch's Law, we shall express the limiting molar conductivity of acetic acid in terms of molar conductivity of other strong electrolytes.

So, we can add the limiting molar conductivity of Sodium-Acetate and Hydrochloric acid, and then subtract the limiting molar conductivity of Sodium Chloride.

The usefulness of this equation is in the fact that the molar conductivity at infinite dilution of weak electrolytes can be expressed with the help of known values obtained from strong electrolytes.

⋆ Hope It Helps.