Question

using krichhoffs rule find the current flowing through each arm hence find the potential difference across 4 ohm resistor​

Answer 1

Explanation:

I3 = I1 + I2

in first mesh,

I3x4 +I1x1 - 2 = 0

I3 x4 + I1 x 1 = 2

in second mesh,

I3x 4 + I2 x 2 - 1 = 0

I3 x 4 + I2 x 2 = 1

using first relation,

I1 x 4+ I2 x 4 + I1 x 1 = 2

I1 x 5 + I2 x 4 = 2 ------1

I1 x 4 + I2 x 4 + I2 x 2 = 1

I1 x 2 + I2 x 6 = 1--------2

x2 in equ 1

X5 in equ 2

we have,

I2 x 8 - I2 x 30 = 4 -5

-I2 x 22 = -1

I2 = 1/22

in equ 1

I1 x 5 + 2/11 = 2

I1 X5 = 2 - 2/11 = 20/11

I1 = 4/11

I3 = 1/22 + 4/11

= 9/22