Question

using L Hospital's rule class 12th math [lim x tents to 0 (e^x-1)tanx/x^2]​

Answer 1

Answer:

lim x-0 (e^x-1)tanx/x^2

lim x-0 (e^x-1)/x ×tanx/x :lim x-0 tanx/x=1

=lim x-0 (e^x-1)/x

using the L HOSPITAL 'S RULE

=lim x-0 e^x-0/1

applying the limit

=e^0/1 :e^0=1

=1/1

=1