Question

Using Ladder Method, prove that for every positive integer n:

1 + 1 ÷ √(2 )+ 1 ÷ √(3 )+...+ 1 ÷ √(n) > 2 √(n + 1 - 1) can u please send me a solved answer.

Answer 1

Answer:

Answer= 1.0

Step-by-step explanation:

1 + 1 ÷ √(2 )+ 1 ÷ √(3 )+...+ 1 ÷ √(n) > 2 √(n + 1 - 1) = 1

By Ladder Method it is true for any positive integer n

Answer 2

Answer:

,s,el I will mark as brainkiest I will mark as brainkiest I will mark as 1vs I