Using Lagrange’s Mean Value Theorem show that
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Using Lagranges mean value theorem, prove that b-ab<log(ba)<b-aa,where 0<a<b. Solution : Lagranges Mean value theorem states that if a function f(x) is continuous and differentiable in interval (a,b), then, f(b)-f(a)b-a=f′(c), where c lies in (a,b).
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0
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Lagrange’s mean value theorem (MVT) states that if a function
f
(
x
)
is continuous on a closed interval
[
a
,
b
]
and differentiable on the open interval
(
a
,
b
)
,
then there is at least one point
x
=
c
on this interval, such that
f
(
b
)
−
f
(
a
)
=
f
′
(
c
)
(
b
−
a
)
.
This theorem (also known as First Mean Value Theorem) allows to express the increment of a function on an interval through the value of the derivative at an intermediate point of the segment.
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