Question

Using lens formula find the position of image it's nature and magnification formed by a concave lens of focal length is 20 cm and object is at 15 cm

Answer 1

Image is formed at 8.57cm. Image is Virtual and erect and diminished

Answer 2

Hope this will help u ...

F=-20cm

u= -15 cm

v=?

Using lens formula ...

1/f= 1/v- 1/u

1/v = 1/f + 1/u

1/v = -1/20- 1/15

1/v = -3-4/60

1/v = -7/60

v= -60/7= -8.5

Image is virtual and erect and diminished in nature...

Or u can refer to the image given below ....

If u liked the answer and it helped u , plz mark it as brainliest