Question

using logarithm differentiation,find dy/dx for (1) y=(cos x)^cos x (2)y=x³sinx/e^x​

Answer 1

Answer:

for 1

(cosx)^cosx

=log(cosx^cosx)

=cosx.log(cosx)

= cosx.1/cosx.(-sinx)+log(cosx).-sinx

= -sinx +-sinx.log(cosx)

simply further by your side