using long division method show that the polynomial p(x)=x3+1 is divisible by q(x)=x+1. verify your result using factor theorem
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Answered by
134
Long division
x^2 - x + 1
____________
x+1 [ x^3 + 1
[ x^3 + x^2
----------------
-x^2 + 1
-x^2 - x
------------
x + 1
x + 1
----------
0
so, the answer is:
x² - x + 1
Using factor theorm:
a³ + b³ = (a + b)(a² – ab + b²)
So, x³ + 1 = x³ + 1³ = (x+1)(x² - 2x + 1)
and (x³ + 1) / (x+ 1) = (x+1)(x² - 2x + 1) / (x + 1)
The (x + 1) brackets cancel out and we are left with
x² - 2x + 1
x^2 - x + 1
____________
x+1 [ x^3 + 1
[ x^3 + x^2
----------------
-x^2 + 1
-x^2 - x
------------
x + 1
x + 1
----------
0
so, the answer is:
x² - x + 1
Using factor theorm:
a³ + b³ = (a + b)(a² – ab + b²)
So, x³ + 1 = x³ + 1³ = (x+1)(x² - 2x + 1)
and (x³ + 1) / (x+ 1) = (x+1)(x² - 2x + 1) / (x + 1)
The (x + 1) brackets cancel out and we are left with
x² - 2x + 1
mitakshi:
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Answered by
34
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