Question

Using long division method, show that x+2 is a factor of x3

+ 8.​

Answer 1

Step-by-step explanation:

I hope it helps a lot

Thank you

Answer 2

Answer:

If an expression is obtained by the product of other expressions then these expressions are called factors of the expression,

Or in other word an expression is divisible by its factor or we get the remainder 0 after dividing an expression by its factor.

Here, the given expression,

$x^3 + 8$

Dividing $x^3 + 8$ by x + 2 the following steps will be follow,

Step 1: Write $x^3 + 8$ ( Dividend ) under the division sign and x + 2 ( divisor ) left side of the division sign.

Step 2: Find out an expression by which we get $x^3$ after multiplying by x + 2

Step 3 : Subtract Dividend by the expression obtained, we will get new dividend

Step 4 : Again find out an expression by which the higher order term of new dividend is cancel out.

Step 5 : Repeat these steps until getting dividend with lower degree than Divisor.

After following this,

We get,

Remainder = 0

Quotient = $x^2 - 2x+4$

Hence, x + 2 is a factor of $x^3 + 8$

#Learn more :

Divide the polynomial using long division method.

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