using long division method show that z^2+3is factor of z^5-9z
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z²+3 ) z^5 - 9z(z³+3z
........... z^5..........3z³
............-
,.................3z³-9z
..................3z³-9z
..................-. +
......................0
As remainder is zero hence it is the factor
........... z^5..........3z³
............-
,.................3z³-9z
..................3z³-9z
..................-. +
......................0
As remainder is zero hence it is the factor
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