Math, asked by pharshita595, 4 months ago

Using long division method
y^4-3y^3+1/2 y^2 divide by 3y​

Answers

Answered by snowykaur595
0

Answer

y^4−3y^3+ 1/2 y^2 by 3y

= y^4 - 3y^3 + 1/2y^2 (whole divided by ). / 3y

= y^4/ 3y - 3y^3/ 3y + 1/ 2×3y y^2

= 1/3y^3 - y^2 + 1/6y

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