Using method of mathematical induction, show that
1. 1+3+5+
(2n - 1) = n2, n EN.
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Step-by-step explanation:
Let P(n): 1 + 3 + 5 + ... + (2n - 1) = n² be the given statement
Put n = 1
Then, L.H.S = 1
R.H.S = (1)² = 1
. L.H.S = R.H.S.
P(n) is true for n = 1
Assume that P(n) is true for n = k.
1 + 3 + 5 + ..... + (2k - 1) = k²
Adding 2k + 1 on both sides, we get
1 + 3 + 5 ..... + (2k - 1) + (2k + 1) = k² + (2k + 1) = (k + 1)²
1 + 3 + 5 + ..... + (2k -1) + (2(k + 1) - 1) = (k + 1)²
P(n) is true for n = k + 1.
by the principle of mathematical induction P(n) is true for all natural numbers 'n'
Hence, 1 + 3 + 5 + ..... + (2n - 1) =n² for all n ϵ n
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