using mirror formula find the position of the object placed in front of converging mirror of focal length f so that the image formed is of same size of the object
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Given,
Size of image, h' =Size of Object,h
m = −v/u = h'/h = 1
or v = −u
Now, using the mirror formula,
1/f = 1/v + 1/u
1/(−f) = 1/(−u) + 1/(−u) = 2/(−u)
[Object distance is always taken negative and the focal length for a concave mirror is negative]
or u = 2f
Thus, the object is placed at a distance '2f' i.e. at the centre of curvature.
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