Question

Using Newton – Raphson method find correct to four decimal places the root between 0 and 1 of the equation x3 – 6x + 4 = 0.

Answer 1

using newton raphson method find correct to four decimal places the root between 0 and 1 of the equation x3-6x-4

Answer 2

Answer:

f(0)=0-6(0)-4

=-4

f(1)=-9

f(2)=-8

f(3)=5

x0=2+3/2

x0=2.5