Using Norton’s theorem, calculate the current in 5ohm resistor in the circuit.
Answers
Answer:
use below trick
Explanation:
(A) Matrix - method for mesh analysis can be used. Mark three loops as shown, in Fig. Resistance- matrix should be evaluated for current in 5- ohm resistor. only, i3 is to be found. R11 = 3, R22 = 6, R33 = 9 R12 = 1, R23 = 2, R13 = 2 Voltage - source will be a column matrix with entries serially as : + 8 volts, + 10volts, + 12volts, (B) Alternatively, Thevenin's can be applied, For this, detach the 5-ohm resistor from its position, Evaluate VTH at the terminals X-Y in Fig. and de- activating the source, calculate the value of RTH as shown in Fig. By observation, Resistance-elements of 2 x 2 matrix have to be noted Raa = 3, Rbb = 5, Rab = 1 Volts, with y positive w.r. to X. RTH can be evaluated from Fig. after transforming delta configuration at nodes B-D-C to its equivalent star, as shown in Fig. (d) Further simplification results into : Rxy =RTH =1.412 ohms Hence, Load Current =VTH/(RL + RTH) =23.3/6.412 =3.643 amp. This agrees with result obtained ealierRead more on Sarthaks.com - https://www.sarthaks.com/490606/determine-current-in-5-resistor-by-anyone-method