Question

Using one identity,
•(a+b)^2 =a^2+2ab+b^2
•(a-b)^2 =a^2-2ab+b^2
•(a+b)(a-b) =a^2-b^2
•(x+a)(x+b) =x^2+x(a+b)+ab

Find (x-3)(x-2)

Answer 1

Answer:

we can solve this question using the fourth identity (x+a)(x+b)=x^2+x(a+b)+ab

answer is x^2-5x+6

Step-by-step explanation:

in this question value of a is -3 and the value of B is -2

1. (x-3)(x-2)=x^2+x{-3+(-2)}+(-3)(-2)
2. (x-3)(x-2)=x^2+x(-3-2)+6 as we know that positive multiply negative is so sign of two will remain negative and in the case of the last term we know that negative multiply negative is always positive so sign of 6 will be positive
3. (x-3)(x-2)=x^2+x(-5)+6 we know that negative and negative are added but the sign will be negative
4. (x-3)(x-2)=x^2-5x+6 we know that negative multiply positive is negative so the sign of 5 x will be negative

hope it will help you

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