Question

Using only 2. 5. 10, 25 and 50 paise coins. The smallest number of coins required to pay exactly 79 aise, 66 paise and re 1.01 to three different persons is

Answer 1

Step-by-step explanation:

if total 246 paise i.e 1.01+66+79=246

by arranging with minimum no. of coins we need to arrange more value coins first to make it equal to 246 paise

1.01 = 50+25+10+10+2+2+2

66 = 50+10+2+2+2

79= 50+25+2+2