Question

Using only a ruler and compass, construct angle ABC = 120°, where AB = BC = 5 cm.
1. Mark two points Dand E which satisfy the condition that they are equidistant from
both BA and BC
2. In the above figure, join AE and EC Describe the figures.
(a) ABCD
(b) ABD
(C) ABE​

Answer 1

Constructed Triangle

Step-by-step explanation:

Step 1 : Draw a line segment AB = 5 cm

Step 2 : Taking Suitable compass width Draw an semicircle taking B as center such that cutting AB at P

Step 3 : keeping compass width same as in step 2 , taking P as center , intersect drawn semicircle at Q

Step 4 : keeping compass width same as in step 2 , taking Q as center , intersect drawn semicircle at R

Step 5 : Draw a ray passing through BR and take length 5 cm from B and mark C

Step 6 : join AC

Step 7 : draw a ray passing through BQ

Step 8 : mark two points D & E on BQ

D & E will be equidistant from BA & BA

ABCD will be kite shaped

Learn more:

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Answer 2

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Step 1 : Draw a line segment AB = 5 cm

Step 2 : Taking Suitable compass width Draw an semicircle taking B as center such that cutting AB at P

Step 3 : keeping compass width same as in step 2 , taking P as center , intersect drawn semicircle at Q

Step 4 : keeping compass width same as in step 2 , taking Q as center , intersect drawn semicircle at R

Step 5 : Draw a ray passing through BR and take length 5 cm from B and mark C

Step 6 : join AC

Step 7 : draw a ray passing through BQ

Step 8 : mark two points D & E on BQ

D & E will be equidistant from BA & BA

ABCD will be kite shaped