Question

Using Pauli’s exclusion principle, how will you prove  that the fourth shell will contain 32 electrons.​

Answer 1

TOTAL ELECTRONS IN A SHELL FORMULA GIVEN BY PAULI EXCLUSIVE PRINCIPLE IS

$2 {n}^{2}$

HERE n INDICATES SHELL NUMBER

HERE NO OF ELECTRONS IN 4 TH SHELL

n=4

$2 \times {4}^{2} = 2 \times 16 = 32$

Answer 2

Answer:

TOTAL ELECTRONS IN A SHELL FORMULA GIVEN BY PAULI EXCLUSIVE PRINCIPLE IS

$2 {n}^{2}$

HERE n INDICATES SHELL NUMBER

HERE NO OF ELECTRONS IN 4 TH SHELL

$\pink {\tt {\huge {n=4}}}$

$\huge \red{ \cal{2 \times {4}^{2} = 2 \times 16 = 32}}$