Question

using peime factorisation ,find out the perfect square among the following

(1) 4624
(2) 9248
(3) 7921

Answer 1

↑ Here is your answer ↓
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(1)

$4624 = 2^4 * 17^2$

Since the exponents are even numbers, it's a perfect square

(2)

$9248 = 2^5 * 17^2$

Since 5 in an odd exponent, it's not a perfect square

(3)

$7921 = 89^2$

No doubt, it's a perfect square!