using phythagoras theorem find the length of second diagnol of a rhombus whose side is 5cm and one of the diagnol is 6cm
Answers
Answered by
3
diagonal one is 6cm (3+3)
side is 5cm
Triplet is 3-4-5
so the diagonal two is 8cm(4+4)
*ANSWER IS 8 CM*
side is 5cm
Triplet is 3-4-5
so the diagonal two is 8cm(4+4)
*ANSWER IS 8 CM*
Answered by
1
As we know phythagorian triplet
half of diagonal is 4
cause ( 3 - 4 - 5 ) 》 phythagorian triplet
so, 4 × 2 = 8
8 cm is measure of second diagonal
half of diagonal is 4
cause ( 3 - 4 - 5 ) 》 phythagorian triplet
so, 4 × 2 = 8
8 cm is measure of second diagonal
Attachments:
Similar questions