Question

using phythagoras theorem find the length of second diagnol of a rhombus whose side is 5cm and one of the diagnol is 6cm

Answer 1

diagonal one is 6cm (3+3)

side is 5cm

Triplet is 3-4-5

so the diagonal two is 8cm(4+4)

*ANSWER IS 8 CM*

Answer 2

As we know phythagorian triplet
half of diagonal is 4
cause ( 3 - 4 - 5 ) 》 phythagorian triplet
so, 4 × 2 = 8
8 cm is measure of second diagonal