Using prime factorisation method, find the hcf.(a)25 and 35 (b) 18 and 15 (c)16,32 and 48 (d) 10,25 and 30 (e)27, 63 and 54 (f)18, 30 and 27
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Answer- (a) 25 and 35.
25= 5x5
35= 5x7
so, H.C.F. = 5
(b) 18 and 52
18=2x3x3
52=2x2x13
so, H.C.F.=2
(c) 16,32 and 48
16=2x2x2x2
32=2x2x2x2x2
48=2x2x2x2x3
so,H.C.F.=2X2X2X2=16
(d) 10,25 and 30
10=2x5
25=5x5
30=2x3x5
so, H.C.F.=5
(e) 27,63 and 54
27=3x3x3
63=3x3x7
54=2x3x3x3
so, H.C.F.=3x3=9
(f) 18,30 and 27
18=2x3x3
30=2x3x5
27=3x3x3
so, H.C.F.=3
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