using prime factorisation method find the hCF and LCM of 30,72 and 432 . also show that HCF ×LCM is not equal to product of two numbers
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Answered by
28
Hi,
Write the numbers 30 ,72,432 into
product of prime .
30 = 2 ×3 ×5
72 = 2 × 2 ×2 × 3 × 3
432 = 2 × 2 × 2 × 2 × 3 × 3 ×3
HCF (30,72,432) = 2 × 3 = 6
LCM( 30,72,432) = 2⁴ × 3³×5 = 2160
I hope this helps you.
:)
Write the numbers 30 ,72,432 into
product of prime .
30 = 2 ×3 ×5
72 = 2 × 2 ×2 × 3 × 3
432 = 2 × 2 × 2 × 2 × 3 × 3 ×3
HCF (30,72,432) = 2 × 3 = 6
LCM( 30,72,432) = 2⁴ × 3³×5 = 2160
I hope this helps you.
:)
Riyagrover:
thanks for help but in this we also show their product is not equal to two number . plzz solve this also
Did u understand what i want to ask
Answered by
17
Heya!
Here is yr answer.....
=> 30 , 72 , 432
30 = 2 × 3 × 5
72 = 2³ × 3²
432 = 2^4 × 3³
HCF = 2×3 = 6
LCM = 2^4 × 3³ × 5 = 2160
HCF × LCM = Product of two nos.
According to ques -- there are three nos.
So, the formula is not valid for our ques!
Hope it hlpz...
Here is yr answer.....
=> 30 , 72 , 432
30 = 2 × 3 × 5
72 = 2³ × 3²
432 = 2^4 × 3³
HCF = 2×3 = 6
LCM = 2^4 × 3³ × 5 = 2160
HCF × LCM = Product of two nos.
According to ques -- there are three nos.
So, the formula is not valid for our ques!
Hope it hlpz...
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