Question

using proper identities,factorise 9y²-6y+1​

Answer 1

Answer:

Step-by-step explanation:

9y²-6y+1

=9y²-3y-3y+1

=3y(3y-1)-1(3y-1)

=(3y-1)(3y-1)

=(3y-1)²

Answer 2

$( {3y})^{2} - 2(3y)(1) + ( {1)}^{2} \\ ( {3y - 1}) ^{2} \\ (3y - 1)(3y - 1)$