using properties of determinant prove that
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put a=1,b=1,c=1
=> L. H. S = | 1. 0. 0 |
| 0. 1. 0|
| 0. 0. 1 |
= 1(1-0) = 1
=> R. H. S = (a+b-c) *(b+c-a)*(c+a-b)
=> R. H. S = (2-1)*(2-1)*(2-1)
=> R. H. S = 1
L. H. S = R. H. S
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Refer to the attachment!!
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