Question

Using properties of proportion, solve for x :

Answer 1

Steps :

1. express (Numerator)/(Denominator) into (Numerator) : (Denominator)

→  2. Follow the steps on the question, use properties of proportion

→ 3. Solve the equation

Step 1

$(x^2+x-3):(x-3)=(4x^2+3x-2):(3x-2)$

Step 2

$(3x-2)(x^2+x-3)=(x-3)(4x^2+3x-2)$

Step 3

$(3x-2)(x^2+x-3)=(x-3)(4x^2+3x-2)$

$3 x^3 + x^2 - 11 x + 6 = 4 x^3 - 9 x^2 - 11 x + 6$

$x^3-10x^2=0$

$x^2(x-10)=0$

∴$x=0$ (Double solution), $x=10$