Using properties of sets show that for any two sets A and B, (A U B) intersection (A U B') = A
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Step-by-step explanation:
Given (A∪B)∩(A∪B')
=(A∪B)∩A)∪((A∪B)∪B')
=A∪((A∪B)∩B')
=A∪(A∩B')∪(B∩B′)
=A∪(A∩B′)=A.
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