Question

using pythagoras theoram prove that in rhombus abcd 4(square of ab) is equal to sum of square of ac and bd

Answer 1

rhombus diagnols bisect each other
use pythagoras theroms in all 4triangles

hypotenuse would be the side of rhombus
sides of rhombus are equal
add all pythagoras equations of 4 triangles

sides are equal so on left side
4ab^2 and other side if you plus it will be ac2 +bd2