Question

using Pythagoras theorem find the length of a seconds diagonal of the Rhombus of side 5 cm having one of the its diagonal as 8cm

Answer 1

Explanation:

the formula of pythagoras theorem is. ..

(hypotenuse)2=(side 1)2+(side 2)2

(hypotenuse)2=(5)2+(8)2

(hypotenuse)2=(25)+(64)

(hypotenuse)2=(89)

then apply square root on both sides

hypotenuse =89