Question

using Pythagoras theorem, find the length of the second diagonal of a rhombus of side 5cm and having one of its diagonal as 8cm.​

Answer 1

Answer:

Step-by-step explanation:

using Pythagoras theorem:

$(half of first diagonal)^{2} = side^{2} - (half of second diagonal)^{2} \\ (half of first diagonal)^{2} = 5^{2} - 4^{2} \\(half of first diagonal)^{2} = 9 \\(half of first diagonal)^{2}= 3\\then, first diagonal = 2*3\\first diagonal = 6$