Question

using Pythagoras Theorem find the length of the second diagonal of a rhombus of side 5 cm and having one of its diagonal as 8cm

Answer 1

The diagonals bisect each other at right angle in a rhombus....... 8/2 =4

By pythogors theorm,

H²=b²+p²

5²=4²+p²

25=16+p²

25-16=p²

√9=p

P=3

So the other diagnol is 3×2 i.e.6

Answer 2

2×3=6 Ans ..................