Question

using Pythagoras theorem, find the value of hypotenuse,if Base=8 and perpendicular=6​

Answer 1

Answer:

hypotenus is equal to under root base square and square of perpendicular

H=√64+36

H=10

Answer 2

Answer:

let, base be=AB = 8

perpendicular be =BC = 6

and hypotenuse be =AC = ?

according to Pythagoras theorm,

( ac^2 = ab^2 + bc^2 )

ac^2 = 8^2 + 6^2

ac^2 = 64 + 36

ac^2 = 100

ac = √100

ac = 10

hope it helps u, hypotenuse is 10.

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