Math, asked by malavikarmenon2004, 11 months ago

using Pythagoras Theorem prove that in a rhombus ABCD,
'4AB^2 = AC^2+ BD^2'

Answers

Answered by prishabbhatt

1

Step-by-step explanation:

by pythagoras theorem

it is ab ² + bc² + ca²

so 4² + 2²+ 2²= 16 + 4 +4

= 24.

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