Question

using pythogorion triplet find the other two number in 8
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Answer 1

Answer:

As we know 2m, m

2

+1,m

2

−1 form a Pythagorean triplet for any number m>1.

Let us assume 2m=8

⇒m=4

Therefore, m

2

+1 = 4

2

+1

⇒16+1=17

and m

2

−1 = 4

2

−1

⇒16−1=15

Hence, the other two members are 15 and 17.

Answer 2

Answer:

2m, m^2-1, m^2+1

2×3, 3^2-1, 3^2+1

6, 8, 10