Using **Python** solve:
Take a 2 digit number as input from the user. Find the square of it, identify the resulting 3 digit
number which has its 2 digits at the rightmost position similar to the original digits
Example: input: AB
AB*AB = CAB for some C
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Explanation:
for i in range (10,101):
sqr = i**2
if str(sqr)[-2:] == str(i):
print(f'{i} : {sqr}')
#this gives the required number and its square
#try this in your ide
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