using quadratic equation fine x²-8x-1280 =0
Answers
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1.1 Factoring x2-8x-1280
The first term is, x2 its coefficient is 1 .
The middle term is, -8x its coefficient is -8 .
The last term, "the constant", is -1280
Step-1 : Multiply the coefficient of the first term by the constant 1 • -1280 = -1280
Step-2 : Find two factors of -1280 whose sum equals the coefficient of the middle term, which is -8 .
-1280 + 1 = -1279
-640 + 2 = -638
-320 + 4 = -316
-256 + 5 = -251
-160 + 8 = -152
-128 + 10 = -118
-80 + 16 = -64
-64 + 20 = -44
-40 + 32 = -8 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -40 and 32
x2 - 40x + 32x - 1280
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-40)
Add up the last 2 terms, pulling out common factors :
32 • (x-40)
Step-5 : Add up the four terms of step 4 :
(x+32) • (x-40)
Which is the desired factorization
