Question

using quadratic formula find the solution of eq 3x2-4x-1=0​

Answer 1

I think the question is wrong

it should be 3x2-4x +1 instead of -1

then the solution will be

3x2-4x+1=0

3x2-3x-x+1=0

(3x2-3x) -(x-1)=0

3x(x-1)-1(x-1) =0

(x-1)(3x-1)=0

x=1 and 1/3

Answer 2

$x = ( - b \: \frac{ + }{} \sqrt{ {b}^{2} - 4ac }) \div 2a \\ \\ 3 {x}^{2} - 4x - 1 = 0 \\ a = 3 \\ b = - 4 \\ c = - 1 \\ \\ x = \frac{ -( - 4) \frac{ + }{} \sqrt{ { - 4}^{2} - 4(3)( - 1) } }{2 \times 3} \\ x = \frac{4 \frac{ + }{} \sqrt{28} }{6} \\ \\ x = \frac{4 + 5.293}{6} \\ x = 1.549 \\ \\ x = \frac{4 - 5.293}{6} \\ x = - 0.215$

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