Question

using quadratic formula method solve the following.abx²+(b²-ac)x-bc=0

Answer 1

Hello dear,
 Here, a=ab

b= b²-4ac

c= -bc

Now, b²-4ac

= (b²-ac)²-4.ab.(-bc)

= b⁴+a²c²-2b²ac+4b²ac

= b⁴+a²c²+2b²ac

= (b²+ac)²

Now, √b²-4ac= b²+ac

Putting it in quadratic formula,

x=(-b ± √b²-4ac)/2a

=> x=(-b²+ac±b²+ac)/2ab

=> x=-b²+ac+b²+ac/2ab or -b²+ac-b²+ac/2ab

=> x= 2ac/2ab or -2b²+2ac/2ab

=> x= c/b or x= 2(-b²+ac)/2ab or x= ac-b²/ab

Hope it helps!