Question

Using quadratic formula solve: p^2x^2+(p^2-q^2)x-q^2=0

Answer 1

x={-(p^2-q^2) +-√[(p^2-q^2)^2+4p^2q^2]}/2p^2
x=-(p^2-q^2)+-(p^2+q^2)/2p^2