Question

Using quadratic formula, solve the following for x:
9x2 - 3(a2 + b2)x + a2b2 = 0
​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

X=b2/3, a2/3

Step-by-step explanation:

Here, a=9, b=-3(a2+b2), c=a2b2

we know that: x=-b +/- sq. root of b2-4ac divide by 2a

x=-[-3(a2+b2)]+/- sq. root of -3(a2+b2)^2- 4x9xab2 divided by 2x9

x=3(a2+b2) +/- sq. root of 9a4 +9b4+ 18a2b2-36a2b2 divided by 18

x=3(a2+b2) +/- sq. root of (3ab2-3b2)^2 divided by 18

x=3(a2+b2) +/- 3(a2-b2) divided by 18

x=3(a2+b2+a2-b2)/18, x=3(a2+b2-a2+b2) / 18

x=a2+a2 / 6, x=3x2xb2 / 18

x=2a^2/ 6,  x=b2/3

x=a2/3, x=b2/3

therefore, x=a2/3, b2/3

hope it will help u :)