Question

Using quadratic formula, solve the quadratic equation for x: x^2-2ax+(a^2+b^2) =0

Answer 1

Solution :

Compare x²-2ax+(a²+b²)=0 with

Ax² + Bx + C = 0 , we get

A = 1 , B = -2a , C = a² + b² ,

Discreminant (D) = B² - 4AC

= ( -2a )² - 4×1×( a² + b² )

= 4a² - 4a² - 4b²

D = -4b²

By Quadratic Formula :

x = [ ( -b ± √D )/2a ]

= [ -(-2a ) ± √(-4b² ) ]/2

= ( 2a ± 2bi )/2

= a ± bi

••••

Answer 2

d=(2a)2-4(a2+b2)
d=4a2-4a2-4b2

d=-4b2

therefore a/formula

x=2a+-√-4b/2
x=2a+2b/2
x=a+or-b