Question

Using Raoult’s law, how will you show

that ∆P = 0 P

1

x2

? Where x2

is the mole

fraction of solute in the solution and

0

P1

vapour pressure of pure solvent.​

Answer 1

Answer:

j+03;9*;19;3;9*9;;1$

Answer 2

Answer:

1. Raoult's law expresses the quantitative relationship between vapour pressure of solution and vapour pressure of the solvent.

2. In solutions of nonvolatile solutes, the law is applicable only to the volatile solvent.

3. The law states that, "the vapour pressure of solvent over the solution is equal to the vapour pressure of pure solvent multiplied by its mole fraction in the solution."

4. Suppose that for a binary solution containing solvent and one nonvolatile solute, P₁ is the vapour pressure of solvent over the solution, X₁ and x2 are the mole fractions of solvent and solute, respectively and P is the vapour pressure of pure solvent, then, P₁ = P₁x₁.

5. Since, x₁ = 1 - X2,

P₁ = Pix₁ = P(1 − x₂) = P₁ - P₁x₂ X2

..P₁-P₁ = P₁x₂ 1X2

..AP= P₁x₂ (AP is the lowering of vapour pressure)