Question

Using rearrangement property find sum of 2/5+-7/9+-11/10+5/18​

Answer 1

Answer:

-6/5

is our answer

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Answer 2

Answer:

$\frac{-6}{5}$ is the required value of $\frac{2}{5} + (\frac{-7}{9} ) + (\frac{-11}{10} ) + \frac{5}{18}$

Step-by-step explanation:

Explanation:

Given in the question that, $\frac{2}{5} + (\frac{-7}{9} ) + (\frac{-11}{10} ) + \frac{5}{18}$

• The sum will always be positive if both numbers are either positive or negative.

• The rules for dividing integers follow the same positive/negative framework as those for multiplication. Two positive or negative numbers are divided to produce a positive number.

• The result is positive when two positive integers are multiplied or divided. The result is positive when two negative numbers are multiplied or divided.

• The result is negative when a positive and a negative number are multiplied or divided.

Step 1:

From the question we have, $\frac{2}{5} + (\frac{-7}{9} ) + (\frac{-11}{10} ) + \frac{5}{18}$

⇒ $(\frac{2}{5} - \frac{7}{9} ) - (\frac{11}{10} - \frac{5}{18})$

⇒ $(\frac{18 - 35}{45}) -( \frac{99 - 25}{90} )$

⇒ $\frac{-17}{45}$ - $\frac{74}{90}$ = $\frac{-34 - 74}{90}$ = $\frac{-108}{90}$

⇒ $\frac{-108}{90}$ = $\frac{-6}{5}$

Final answer:

Hence, $\frac{-6}{5}$ is the required value of $\frac{2}{5} + (\frac{-7}{9} ) + (\frac{-11}{10} ) + \frac{5}{18}$

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