Question

Using relation, write the Pythagorean triplet whose smallest number is 3?​

Answer 1

Pythagoras triplets are of the form 2m, m² -1 and m² + 1.

It is given that the smallest number is 8.

So, 2m = 3

m = 4

Now,

second number = m² -1 = 4² – 1 = 15

third number = m² + 1 = 4² + 1 = 17.

Hence, the triplet is 8, 15 and 17.

This can be verified as

7² = 3 + 10

289 = 64 + 225

289 = 289.

Hence, p

Step-by-step explanation:

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