Question

using Remainder thechen find the
lu
when
x cube - 6x²+2x-4 is divided by 3x-1​

Answer 1

Answer:

3x-1=0

3x=1

x=1/3

P(x)=x³-6x²+2x-4

P(1/3)=(1/3)³-6(1/3)²+2(1/3)-4

P(1/3)=1/27-6×1/9+2/3-4

P(1/3)=1/27-2/3+2/3-4

P(1/3)=1/27-4

P(1/3) =(1-108)/27

P(1/3)= - 107/27