Question

Using Remainder Theoram Factorise:
6x^3-25x^2+32x-12

Answer 1

Answer:

F(x) = 6x³-25x²+32x-12 on putting x = 2 we get f(x) = 0 , hence (x-2) is a factor of given polynomial.

(x-2)(6x²-13x+6)

= (x-2)(6x²-9x-4x+6)

= (x-2){3x(2x-3)-2(2x-3)}

= (x-2)(2x-3)(3x-2)

Step-by-step explanation:

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