using remainder theoram, find the remainder when p(x)=4xcube-12xsquare+14x-3 is devided by q(x)=2x-1
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Answered by
4
x=1/2
4•1/8-12•1/4+14•1/2-3
1/2-3+7-3
1/2+7-6
1/2+1
3/2
1.5
4•1/8-12•1/4+14•1/2-3
1/2-3+7-3
1/2+7-6
1/2+1
3/2
1.5
Answered by
1
Finding zero of the q(x), you get x=1/2
4(1/2)cube-12(1/2)sq+14(1/2)-3
4(1/8)-12(1/4)+14(1/2)-3
(1/2)-3+7-3
(1/2)+1
Using fraction division ur answer will be
3/2
4(1/2)cube-12(1/2)sq+14(1/2)-3
4(1/8)-12(1/4)+14(1/2)-3
(1/2)-3+7-3
(1/2)+1
Using fraction division ur answer will be
3/2
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