Using remainder theoram,find the remainder when x⁴-3x³+2x²-4
is divided by x+2
Answers
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Given :-
x⁴ - 3x³ + 2x² - 4
( x - 2 ) when divides leaves remainder
Required to find :-
- Find the remainder ?
Method used :-
>> Remainder Theorem <<
Solution :-
Given information :-
x⁴ - 3x³ + 2x² - 4
( x + 2 ) when divides leaves remainder
we need to find the remainder theorem
So,
Let's consider the given polynomial as ;
p ( x ) = x⁴ - 3x³ + 2x² - 4
( x + 2 ) when divides p ( x ) it leaves remainder
So,
Let,
x + 2 = 0
x = - 2
p ( - 2 ) = ( - 2 )⁴ - 3 ( - 2 )³ + 2 ( - 2 )² - 4
p ( - 2 ) = 16 - 3 ( - 8 ) + 2 ( 4 ) - 4
p ( - 2 ) = 16 + 24 + 8 - 4
p ( - 2 ) = 48 - 4
p ( - 2 ) = 44
Therefore ,
When ( x + 2 ) divides p ( x ) it leaves remainder as 44
Additional Information :-
The remainder theorem states that when f ( x ) is divided by ( x - a ) the remainder will be equal to the value which we get by substituting this value of " a " in place of x in p ( x )
This is represented as ;
p ( x ) ÷ ( x - a ) = x
p ( a ) = x
Here, the value is same in both cases
Example ,
p ( x ) = x² - 2x + 1 ÷ ( x - 1 )
So,
When ( x + 1 ) divides p ( x ) the remainder is zero
Now substitute the 1 in value of p ( x )
So,
p ( 1 ) = ( 1 )² - 2(1) + 1
p ( 1 ) = 1 - 2 + 1
p ( 1 ) = 2 - 2
p ( 1 ) = 0
Hence,
In this both cases the value is same .
This is defined in the remainder theorem .