Question

using remainder theoram find the remainder (x³_6x²+9x+3) is divided by (x-1)​

Answer 1

Answer:

To find it, first,

(x-1) = 0

x = 1

Put x = 1 in the function.

1³ - 6×1² + 9×1 + 3

1 -6 +9 +3

7 is the remainder.

Answer 2

Answer:

$Dividend: x^3-6x^2+9x+3$

$Divisor = (x-1)$

Remainder Theorem = Let p(x) be a polynomial in x of degree greater than or equal to 1 and 'a' be any real number. If p(x) is divided by (x – a), then the remainder is p(a).

The remainder when p(x) is divided by (x-1) is P(1)

$P(1) = x^3-6x^2+9x+3$

$P(1) = (1)^3-6(1)^2+9(1)+3$

$P(1) = 1-6+9+3$

        $= 7$

Therefore, the remainder will be 7 after dividing (x³ - 6x² + 9x + 3) by (x - 1).