Question

using remainder theorem factories 2x³+x²-13x+6

Answer 1

2x3-x2-13x-6

Final result :

(2x + 1) • (x + 2) • (x - 3)
Step by step solution :

Step 1 :

Equation at the end of step 1 :

((2x3 - x2) - 13x) - 6
Step 2 :

Checking for a perfect cube :

2.1 2x3-x2-13x-6 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: 2x3-x2-13x-6

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -13x-6
Group 2: 2x3-x2

Pull out from each group separately :

Group 1: (13x+6) • (-1)
Group 2: (2x-1) • (x2)

Answer 2

2x + 1) • (x + 2) • (x - 3)

Step by step solution :

Step  1  :

Equation at the end of step  1  :

((2x3 - x2) - 13x) - 6

Step  2  :

Checking for a perfect cube :

 2.1    2x3-x2-13x-6  is not a perfect cube 

Trying to factor by pulling out :

 2.2      Factoring:  2x3-x2-13x-6 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -13x-6 
Group 2:  2x3-x2